## MATH 114N Week 3 Test 1 Review Attempt 2 | Solutions

**Question: **If an object is projected upward with an initial velocity of 126 ft per sec, its height h after t seconds is h = -16ˆ2+126t. Find the height of the object after 2 seconds.

**2. Question: **What polynomial can be factored as (a + 4)(a + 7)?

**3. Question: **If an object is projected upward with an initial velocity of 127 ft per sec, its height h after t seconds is h = -16t^{2}+127t. Find the height of the object after 25 seconds.

**4. Question: **Factor the trinomial.

v^{2} + 10vf + 16f^{2}

**5. Question: **Complete the factoring.

3a^{2} + 12a – 136 = 3( )( )

__ ____ __

3a^{2} + 12a – 136 = 3 (a – 2)(a + 6)

**6. Question: **The middle term of the trinomial has been rewritten. Now factor by grouping.

6r^{2} + 13rs + 6s^{2} = 6r^{2} + 4rs + 9rs + 6s^{2}

__ ____ __

6r^{2} + 4rs + 9rs + 6s^{2}= (3r + 2s)(2r + 3s)

**7. Question: **Complete the factoring.

5y + 30 = 5( )

**8. Question: **Factor completely.

81b^{2} – 100t^{2}

**9. Question: **Factor completely.

c^{2} + 49

**10. Question: **The area of a parallelogram is given by the formula A = bh. The area of parallelogram on the right is 52 sq. units. Find its base and height.

**11. Question: **Factor the trinomial by grouping.

16m^{2} – 16m – 5

__ ____ __

## STATUS

16m^{2} – 16m – 5= (4m + 1)(4m – 5)

**12. Question: **Which of the following are differences of square.

x^{2} – 9, y^{2} + 36, 2a^{2 }– 25, 4z^{2} – 16

**13. Question: **Which of the following are differences of square.

a^{2} – 16, y^{2} + 4, 8m^{2 }– 25, 9x^{2} – 1

**14. Question: **The product of two consecutive positive integers is 29 more than their sum. Find the integers.

**15. Question: **Factor the special product.

16r^{2} – 56r + 49

**16. Question: **Complete the factoring.

10s^{3} – 22s^{2} + 4s = 2s(__ _)__

= 2s(__ ) ( )__

**17. Question: **Factor. Note that the middle term has already been split.

28a^{2} – 24a + 21a – 18

__ ____ __

28a^{2} – 24a + 21a – 18 = (7a – 6)(4a + 3)

**18. Question: **Rosa works due north of home. Her husband Ray works due east. They leave for work at the same time. By the time Rosa is 3 miles from home, the distance between them is one mile more than Ray’s distance from home. How far from home is Ray?

**19. Question: **Solve.

x^{2} – 22x + 21 = 0

**20. Quesution: **Factor.

8s^{2} + 4s

**21. Question: **Solve using the zero factor property.

(3v + 7)(v + 6) = 0

**22. Question: **Factor completely.

9x^{2} – 12xy + 4y^{2}

**23. Question: **Complete the factoring.

2x^{3} + 10x^{2} + 8x

**24. Question: **Factor by grouping.

x^{3} + 7x^{2} + 9x + 63

**25. Question: **Factor the trinomial.

v^{2} + 3v + 2

**26. Question: **Find the greatest common factor (GCF) of 24x and 21.